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Using two constexpr's without initialization

If I have a constexpr function with two arguments, is it possible to get the compiler to store the result of one of the constexpr's to a variable that only has constexpr's defined on it?

In the sample below I would like to use var b in a constant expression:

#include

constexpr int foo(const int &a, const int b) {

if constexpr (b == 3)

return 1;

else

return a + b;

}

int main() {

static_assert( foo(1,3) == 2, "" );

}

I don't think it's possible to make the compiler use a constexpr on 0b46394aab